Soft WDT reset Error can Fixed with single line code in Nodemcu (IOT)

when you use while loops in your codeing with delay function (in nodemcu),
you must face this error Soft WDT reset.
lets see a example

//////example/////////

int motor = D1;//5;     // LED pin
int encoder = A0;//4; // push button is connected
void setup() {
Serial.begin(9600);
        pinMode(motor, OUTPUT);   // declare LED as output
        pinMode(encoder, INPUT);
}

void loop() {

   Serial.println(analogRead(encoder));
    while(analogRead(encoder)>=400){
      digitalWrite(motor, HIGH);
      Serial.println(analogRead(encoder));
      }
      digitalWrite(motor, LOW);
}

when you run like this code you will face below prblms

Soft WDT reset

ctx: cont
sp: 3ffef120 end: 3ffef390 offset: 01b0

>>>stack>>>
3ffef2d0: feefeffe feefeffe feefeffe feefeffe
3ffef2e0: 40219851 00000004 3ffe835c 33383980
3ffef2f0: 40219af3 00000004 3ffe835c 0000018f
3ffef300: 3ffee338 00000004 3ffe835c 00000000
3ffef310: 40212d38 00000000 3ffee338 40201ee1
3ffef320: 3ffe8468 000003d7 3ffee338 40201fcb
3ffef330: 00000000 000003d7 40203358 3ffe8360
3ffef340: 40201126 3ffe835c 3ffee338 40201ff4
3ffef350: feefeffe 3ffe835c 3ffe8360 40201cb5
3ffef360: 00000000 00000000 00000001 3ffee35c
3ffef370: 3fffdad0 00000000 3ffee354 40202184
3ffef380: feefeffe feefeffe 3ffee370 40100114
<<<stack<<<
? )�

if you got like this error you can easily fix it
add
        dealy(0);
inside the loop .

example

int motor = D1;//5;     // LED pin
int encoder = A0;//4; // push button is connected
void setup() {
Serial.begin(9600);
        pinMode(motor, OUTPUT);   // declare LED as output
        pinMode(encoder, INPUT);
}

void loop() {

   Serial.println(analogRead(encoder));
    while(analogRead(encoder)>=400){
      digitalWrite(motor, HIGH);
      Serial.println(analogRead(encoder));
      delay(0);                                               //added here
      }
      digitalWrite(motor, LOW);
   delay(2);
}